LOGARITHMS J2

 

Evaluate Log10000 -  log 0.001 - log 0.0001+ log 0.00001

 

Solution

 

= Log10000 -  log 0.001 -  log 0.0001+ log 0.00001

 

= Log10⁴ -  log 10^-3 – log 10^-4 + log 10^-5

 

= 4Log10 - (-3 log 10) – (-4log 10) + (-5log 10)

 

= (4x1) - (-3x1) - (-8x1) + (-5 x 1)

 

= 4 - (-3) – (-4) -5

 

= 4 + 3 + 4 - 5

 

= 11 – 5

 

= 6 ans.

 

  

Hence Log10000 -  log 0.001-  log 0.0001+ log 0.00001 = 6

 

 

TRY THIS……………………… 

 

 

Evaluate Log1000 -  log 0.001 - log 0.00000001+ log 0.00001