Thursday, 11 May 2023

G.PROGRESSION J1

 The 1st term of a geometric progression is 7 and the 5th term is 112. Find i)the common ratio. ii) 12th term

 

Solution

 

G1=7, G5=112, n=5

 

i) Gn = G1rn-1;

 

G5 = G1r5-1;

 

G5 = G1r4;

 

112 = 7 x r4;

 

112 = 7r4;

 7       7

 

16 = r4;  Finding the fourth root of 16,

 

r = 2

 

 

 

Hence the common ratio is 2.

 

ii)  12th term

 

Gn = G1rn-1;

 

G12 = G1r12-1;

 

G12 = G1r11;

 

G12 = 7 x 211;

 

G12 = 7 x 2048;

 

G12 = 14336

 

Hence the 12th term is 14336

 

TRY THIS………………………….. 

 

The 1st term of a geometric progression is 2 and the 6th term is 486. Find i) the common ratio. ii) 10th term

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