ALGEBRA - I1

 

The sum of four consecutive numbers is 474. Find the 3rd number.

 

Solution

 

Let the numbers be as shown in the table below

 

1st number	2nd number	3rd number	4th number	TOTAL
n	n+1	n+2	n+3	474

 

Then, n + (n+1) + (n+2) + (n+3) = 474

 

4n + 1+2+3= 474

 

4n + 6 = 474

 

4n = 474 – 6

 

4n = 468 

 

4n = 468

 4        4

 

n = 117

 

3rd number = n +2

 

                   = 117 + 2

 

                   = 119

 

Hence the 3rd number is 119

 

TRY THIS………………….. 

 

The sum of four consecutive numbers is 1006. Find the largest number.