Monday 3 April 2023

LOGARITHMS - I1

 Evaluate Log2(512 ÷ 8).

 

Solution

 

= Log2(512 ÷ 8)

 

= Log2512 -  Log28          (applying the product rule)

 

= Log229 -  Log223             ( 512= 29 and 8=23 )

 

= 9Log22 -  3Log22       ( remember  Logaac = cLogaa )

 

= (9 x 1) -  (3 x 1)          ( remember  Logaa = 1 )

 

= 9 - 3

 

= 6 answer

 

 

TRY THIS...............

 

Evaluate Log2(2048 - 32).

 

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