ARITHMETIC PROGRESSION 1

The 1st term of an A.P. is 70 and the common difference is 24. Find the 10th term.

Solution

A₁= 70, d = 24

A_n = A₁ + (n-1)d

A₁₀ = A₁ + (10-1)d

A₁₀ = A₁ + 9d

A₁₀ = 70 + (9x24) [ after substituting A₁= 70, d = 24 as given above]

∴ A₁₀ = 70 + 216

A₁₀ = 286

Hence the 10th term is 286.

TRY THIS……………

The 1st term of an A.P. is 27 and the common difference is 33. Find the 7th term.