Find the sum
of the 1st ten terms of the geometrical progression 2+4+8+16+…….
Solution
G1
= 2, r=2, n=10
Sn = G1(rn-1)
r-1
S10 = 2(210-1)
2-1
S10 = 2(210-1)
1
S10 = 2(210-1)
S10 = 2(1024-1)
S10 = 2(1023)
S10 = 2046
Hence the
sum of the 1st ten terms is 2046.
TRY THIS………………….
Find the sum
of the 1st twelve terms of the geometrical progression 2+4+8+16+…….
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