ALGEBRA 4

The sum of four consecutive numbers is 362. Find the 4th number.

Solution

Let the numbers be as shown in the table below

1st number	2nd number	3rd number	4th number	TOTAL
n	n+1	n+2	n+3	362

Then, n + (n+1) + (n+2) + (n+3) = 362

4n + 1+2+3= 362

4n + 6 = 362

4n = 362 – 6

4n = 356 

4n = 356

 4       4

n = 89

4th number = n + 3

                 = 89 + 3

                 = 92

Hence the 4th number is 92

TRY THIS.....................................

The sum of four consecutive numbers is 358. Find the 4th number.