A settlement has a
population of 2000 people. Each year 5%of the people leave the settlement. How
many people will remain after 3 years?

__solution__
f(t) = A ( 1 -5/100)

^{t}
= 2000(1 – 0.05)

^{t}
= 2000 x (0.95)

^{3}
= 2000 x 0.95 x 0.95 x 0.95

= 2000 x 0.857375

= 1714.75 (1715 approximate)

__Therefore there will be 1715 people remaining after three years of decay__
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