The sum of the 1st five terms of a geometrical
progression is 341. If the common ratio is 4 find the 1st term.
Solution
S5 = 341 G1
= ?, r=4, n=5
Sn
= G1(rn-1)/ r-1
S5
= G1(r5-1)/ r-1
341=
G1(45-1)/ 4-1
341=
G1(1024-1)
3
3
x 341= G1(1023)
1023=
1023 G1
1023= G1
1023
G1
= 1
Hence the 1st term is 1.
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