A settlement has a
population of 2000 people. Each year 5%of the people leave the settlement. How
many people will remain after 3 years?
solution
f(t) = A ( 1 -5/100)t
= 2000(1 – 0.05)t
= 2000 x (0.95)3
= 2000 x 0.95 x 0.95 x 0.95
= 2000 x 0.857375
= 1714.75 (1715 approximate)
Therefore there will be 1715 people remaining after three
years of decay
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