The sum of
the 1st five terms of a geometrical progression is 484. If the common ratio is
3 find the 1st term.
solution
S5 =
484 G1 = ?, r=3, n=5
Sn = G1(rn-1)/ r-1
S5 = G1(r5-1)/ r-1
484= G1(35-1)/ 3-1
484= G1(243-1)
2
2 x 484= G1(242)
968= 242 G1
4 968 = G1
G1 = 4
Hence the 1st term is 4.
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