In Biology test the
following marks were recorded.
marks
|
10-19
|
20-29
|
30-39
|
40-49
|
50-59
|
No. of students
|
2
|
4
|
5
|
6
|
3
|
Calculate the mean.
Solution
In this question we are
going to apply the method of assumed mean.
Here you are required to
produce the frequency distribution table.
Let us take 34.5 as our
assumed mean(A). Take away the assumed mean from each class mark.
Class
interval
|
Class mark
(x)
|
d=x-A
|
Frequency(f)
|
fx
|
fd
|
10-19
|
14.5
|
-20
|
2
|
29
|
-40
|
20-29
|
24.5
|
-10
|
4
|
98
|
-40
|
30-39
|
34.5
|
0
|
5
|
172.5
|
0
|
40-49
|
44.5
|
10
|
6
|
267
|
60
|
50-59
|
54.5
|
20
|
3
|
163.5
|
60
|
|
∑f = 20
|
∑fx = 730
|
∑fd = 40
|
Mean = A + ∑fd
∑f
Mean = 34.5 + 40
20
Mean = 34.5 + 2
Hence Mean = 36.5
Also you can prove your
answer by using the normal formula of calculating mean, that is ∑fx/∑f and try
to see if you get the same answer.
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