Saturday 3 August 2013

SEQUENCE&SERIES-4


The 1st term of an A.P. is 10 and the common difference is 58. Find the 12th term.

Solution

A1= 10, d = 58

An = A1 + (n-1)d   [ formula for n terms ]

A12 = A1 + (12-1)d

A12 = A1 + 11d    [ formula for 12 terms ]

A12 = 10 + (11 x 58)

A12 = 10 + 638

A12 = 648


Hence the 12th term is 648.



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