Saturday 5 February 2022

LOGARITHMS E1

 Evaluate Log100 +  log 0.001 -  log 0.00000001

 

Solution

 

= Log1000 +  log 0.001 -  log 0.00000001

 

= Log103 +  log 10-3 – log 10-8

 

= 3Log10 + (-3 log 10) – (-8log 10)

 

= (3x1) + (-3x1) - (-8x1)

 

=3 + (-3) – (-8)

 

= 3 – 3 + 8

 

=8

 

 

Hence Log100 +  log 0.001-  log 0.00000001 = 7

 

 

TRY THIS……………………… 

 

 

Evaluate Log10000 +  log 0.00001 -  log 0.0000000000001

No comments:

Post a Comment