Find a linear function f(x) with
gradient -6 which is such that f(8)=12.
Solution.
m=-6, points = [8,12] and [x, f(x)]
m = y2-y1/x2-x1
-6 = [f(x) – 12]/x-8
f(x)-12=-6(x-8) [after cross
multiply]
f(x)-12=-6x+48
f(x)=-6x+48+12
f(x)=-6x+60
A linear
function is f(x) = -6x+ 60.
TRY THIS……….
Give out a linear function f(x) with
gradient -5 and f(6)=19
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