LOGARITHMS E2

 Change the following into exponential form

i) Log₇ 49 = 2

ii) Log₂ 16 = 4

iii) Log₈ 1 = 0

iv) log₅ (¹/₁₂₅) = -3

Solution

 

i) 7² = 49 ⇔ log₇ 49 = 2

ii) 2⁴ = 16 ⇔ Log₂ 16 = 4

iii) 8⁰ = 1 ⇔ log₈ 1 = 0

iv) 5^-3 = ¹/₁₂₅ ⇔ log₅ (¹/₁₂₅) = -3

TRY THIS…………….

 

Change the following into exponential form

i) Log₁₁ 121 = 2

ii) Log₃ 81 = 4

iii) Log₂₆1 = 0

iv) log₄ (¹/₆₄) = -3