WORD PROBLEMS 3

Wema, Kim and Fred shared 1200 sweets such that Wema got 20 sweets less than Kim while Fred got three as much as what Ana got. Find those given to Fred.

Solution

The starting point is Kim. Let the sweets given to Kim be x. See the table below:

WEMA	KIM	FRED	TOTAL
x-20	x	3(x-20) =3x-60	1200

  

Then;

ANA + JOY + FRED = 1200

x-20 + x + 3x-60 = 1200

x + x + 3x - 60 - 20 = 1200

5x - 80 = 1200    [since -60-20 = -80]

5x = 1200 + 80

5x = 1280

5x = 1280

5       5

x = 256

The sweets given to Fred

= 3x – 60

= 3(256) – 30

= 768 – 30

= 738

Hence Fred got 738 sweets.

TRY THIS………………………

Kemi, Roy and Isaya shared 550 sweets such that Kemi got 10 sweets less than Roy while Isaya got four as much as what Kemi got. Find those given to Isaya.   [360 answer]