A bag
contains 2 red balls and 6 blue balls. Two balls are taken from the bag. What
is the probability that they are both red?
Solution
(This is a
problem with replacement)
n(R) = 2,
n(B) = 6, n(S) = 8
P(R) = n(2)
n(6)
1st pick = 2/8
2nd pick = 2/8
as well.
P(RR) = 2
x 2
8 8
P(RR) = 4 /64
= 1/16
Therefore
Probability of drawing a red ball is 1/16
TRY THIS ..............
A bag
contains 9 purple stones and 11 blue stones. Two stones are taken from the bag.
What is the probability that they are both blue?
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