A line passes through (4a, 9) and
(8, 5a). If its slope is 2, find a.
Solution
x1=4a, y1 = 9, x2 = 8, y2 = 5a
Slope(m) = y2 –
y1
x2 – x1
2 = 5a – 9
8 – 4a
2 = 5a
– 9 [cross multiplying]
1 8 – 4a
2(8 – 4a) = 5a – 9
16 – 8a = 5a – 9
16 – 8a + 9 = 5a
16 + 9 = 5a+ 8a
25 = 13a
25 = 13a
13 13
25/13 = a
Hence
a = 25/13
TRY
THIS.................................
A line passes through (4e, 9) and
(8, 42e). If its slope is 2, find e.
No comments:
Post a Comment