MATHEMATICS PROBLEM SOLVER

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Saturday, 30 January 2016

LOGARITHMS 1

Evaluate Log₂(512 ÷ 8).

Solution

= Log₂(512 ÷ 8)

= Log₂512 - Log₂8 (applying the quotient rule)

= Log₂2⁹ - Log₂2³ ( 256= 2⁸ and 8=2³ )

= 9Log₂2 - 3Log₂2 ( remember Log_aa^c= cLog_aa )

= (9 x 1) - (3 x 1) ( remember Log_aa= 1 )

= 9 - 3

= 6

hence Log₂(128 ÷ 64) = 6

TRY THIS...............

Evaluate Log₂(1024 ÷ 32).

MATHEMATICS PROBLEM SOLVER

Saturday, 30 January 2016

LOGARITHMS 1

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