MATHEMATICS PROBLEM SOLVER

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Tuesday, 15 September 2015

LOGARITHMS 3

Evaluate Log₂16 + Log₂10 + Log₂40

Solution

= Log₂16 - Log₂10 + Log₂40

= Log₂(16x40)

= Log₂(640)

= Log₂(64)

= Log₂2⁶)

= 6Log₂2

= 6 x 1

= 6

Hence Log₂16 + Log₂10 + Log₂40 = 6

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Evaluate Log₂8 - Log₂7 + Log₂ 224

MATHEMATICS PROBLEM SOLVER

Tuesday, 15 September 2015

LOGARITHMS 3

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