Evaluate Log2(32
x 2).
Solution
= Log2(32
x 2)
= Log232
+ Log22 (applying the product rule)
= Log225
+ Log221 (32= 25 and 2=21 )
= 5Log22
+ 1Log22 ( remember Logaac = cLogaa
)
= (5 x 1)
+ (1x 1) ( remember Logaa = 1 )
= 5 + 1
= 6
hence Log2(32 x 2) = 6
TRY THIS………………
Evaluate Log2(128
x 4).
No comments:
Post a Comment