Wednesday, 5 June 2013

LOGARITHMIC EQUATIONS - 2




If log5(2x + 1)=2; find x
  
 Solution

log5(2x + 1)=2
(2x + 1)=52                         

2x + 1=25

2x =25 – 1

2x = 24

2x = 24   
2        2

x = 12

Hence x = 12        


 

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