ALGEBRA - 3

The sum of four consecutive numbers is 362. Find the 3rd number.

Solution

Let the numbers be as shown in the table below

1st number	2nd number	3rd number	4th number	TOTAL
n	n+1	n+2	n+3	362

Then, n + (n+1) + (n+2) + (n+3) = 362

4n + 1+2+3= 362

4n + 6 = 362

4n = 362 – 6

4n = 356 

4n = 356

 4        4

n = 89

3rd number = n +2

                       = 89 + 2

                      = 91

Hence the 3rd number is 91