Friday, 7 June 2013

FUNCTIONS - 3




If F(x) = log2x, Find F(1/32)

Solution

F(x) = log2x

F(1/32) = log2(1/32)

F(1/32) = log232-1

F(1/32) = log2(25)-1

F(1/32) = log22(5 x -1)

F(1/32) = log22-5

F(1/32) = -5log22

F(1/32) = -5 x 1

F(1/32) = -5

Therefore F(1/32) = -5

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