LOGARITHMS 3

Evaluate Log₂(2048 ÷ 16).

Solution

= Log₂(2048 ÷ 16)

= Log₂2048 - Log₂16          (applying the product rule)

= Log₂2¹¹ -  Log₂2⁴             (2048= 2¹¹ and 16=2⁴ )

= 11Log₂2 -  4Log₂2       ( remember  Log_aa^c = cLog_aa )

= (11 x 1) -  (4 x 1)          ( remember  Log_aa = 1 )

= 11 - 4

= 7

Hence  Log₂(2048 ÷ 16) = 7

TRY THIS………………

Evaluate Log₂(1024÷128).