ALGEBRA-4

The sum of five consecutive numbers is 590. Find the 4th number.

Solution

Let the numbers be as shown in the table below

1st number	2nd number	3rd number	4th number	5th number	TOTAL
n	n+1	n+2	n+3	n+4	590

Then, n + (n+1) + (n+2) + (n+3)+ (n+4) = 590

5n + 1+2+3 +4= 590

5n + 10= 590

5n = 590 -10

5n = 580

5n = 580

 5        5

n = 116

4th number = n +3

                       = 116 + 3

                       = 119

Hence the 4th number is 119