Tuesday 26 September 2023

LOGARITHMS K5

 

If nLog5125= Log21024 ; Find n

 

Solution

 

nLog5125= Log21024

 

nLog553= Log2210  [Since 125=53  and 1024=210]

 

3nLog55= 10Log22

 

3n x 1= 10 x 1   [since Logaa=1]

 

3n= 10

 

n = 10/3 answer

 

TRY THIS………

 

If uLog5125= Log22567 ; Find u


No comments:

Post a Comment