ALGEBRA K3

 

The sum of four consecutive numbers is 606. Find the 3rd number.

 

Solution

 

Let the numbers be as shown in the table below

 

1st number	2nd number	3rd number	4th number	TOTAL
n	n+1	n+2	n+3	1606

 

Then, n + (n+1) + (n+2) + (n+3) = 1606

 

4n + 1+2+3= 1606

 

4n + 6 = 1606

 

4n = 1606 – 6

 

4n = 1600 

 

4n = 1600

 4        4

 

n = 400

 

3rd number = n +2

 

                   = 400 + 2

 

                   = 402

 

Hence the 3rd number is 402

 

TRY THIS………………….. 

 

The sum of five consecutive numbers is 610. Find the largest number.