ALGEBRA D1

 

The sum of four consecutive numbers is 606. Find the 3rd number.

 

Solution

 

Let the numbers be as shown in the table below

 

1st number	2nd number	3rd number	4th number	TOTAL
n	n+1	n+2	n+3	606

 

Then, n + (n+1) + (n+2) + (n+3) = 606

 

4n + 1+2+3= 606

 

4n + 6 = 606

 

4n = 606 – 6

 

4n = 600 

 

4n = 600

 4        4

 

n = 150

 

3rd number = n +2

 

                   = 150 + 2

 

                   = 152

 

Hence the 3rd number is 152

 

TRY THIS………………….. 

 

The sum of five consecutive numbers is 1035. Find the largest number.