Tuesday, 9 October 2018

MID POINT 1


Find a and b if the midpoint of a line from (a, 6) to (8, b) is
(30, 7)

Solution

x1=a, x2=8, y1=6, y2=b.

(30, 7)= (x1 + x2, y1 + y2)
                   2             2

(30, 7)= (a + 8,  6 + b)
                  2          2


Equating equal values of x;

30= a + 8
         2      

2 x 30= (a + 8)  x 2 1
                2 1     

60 = a + 8

60-8 = a

a = 52.

Equating equal values of y;

7 = 6 + b
        2

2 x 7= (6 + b)  x 2 multiplying by 2 both sides.
                2 1     

14 = 6 + b

14 – 6 = b

b = 8

Hence a = 52 and b=8

TRY THIS……………………..



Find m and n if the midpoint of a line from (m, 19) to (13, n) is (9, 11)

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