Find a and b if the midpoint of a
line from (a, 6) to (8, b) is
(30, 7)
Solution
x1=a, x2=8, y1=6, y2=b.
(30, 7)= (x1 + x2, y1 + y2)
2
2
(30, 7)= (a + 8, 6 +
b)
2 2
Equating equal values of x;
30= a + 8
2
2 x 30= (a + 8) x 2
1
60 = a + 8
60-8 = a
a = 52.
Equating equal values of y;
7 = 6 + b
2
2 x 7= (6 + b) x 2
1 multiplying by 2 both
sides.
14 = 6 + b
14 – 6 = b
b = 8
Hence a = 52 and b=8
TRY THIS……………………..
Find m and n if the midpoint of a line from (m,
19) to (13, n) is (9, 11)
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