ALGEBRA 2

The sum of five consecutive numbers is 525. Find the 4th number.

Solution

Let the numbers be as shown in the table below

1st number	2nd number	3rd number	4th number	5th number	TOTAL
n	n+1	n+2	n+3	n+4	525

Then, n + (n+1) + (n+2) + (n+3) + (n+4) = 525

5n + 1+2+3+4= 525

5n + 10= 525

5n = 525- 10

5n = 515 

5n = 515

5       5

n = 103

4th number = n + 3

                   = 103 + 3

                   = 106

Hence the 4th number is 106

TRY THIS………………….. 

The sum of five consecutive numbers is 1815. Find the largest number.