Friday, 27 April 2018

LOGARITHMS 2


If Log(30x-90/5+x) = 1. Find x.

Solution

Log(30x-90/5+x) = 1.

Log10(30x-90/5+x) = 1.

 30x-90 = 101. After changing into exponential form
   5+x

30x-90 = 10    since [101=10]
   5+x

30x-90 = 10(5+x)    after cross multiply
  
30x-90 = 50+10x

30x-10x = 50+90 [collecting like terms]

20x = 140

x=7  [after dividing by 20 both sides]

Hence x=7.

TRY THIS……………


If Log(30x-50/5+x) = 1. Find x.

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