WORD PROBLEMS 1

Ana, Joy and Fred shared 2400 sweets such that Ana got 50 sweets less than Joy while Fred got three as much as what Ana got. Find those given to Fred.

Solution

The starting point is Joy. Let the sweets given to Joy be x. See the table below:

ANA	JOY	FRED
x-50	x	3(x-50)=3x-150

  

Then;

ANA + JOY + FRED = 2400

x-50 + x + 3x-150 =2400

x + x + 3x - 150 - 50 = 2400

5x - 200 = 2400

5x = 2400 + 200

5x = 2600

5x = 2600

5       5

x = 520

The sweets given to Fred

= 3x – 150

= 3(520) – 150

= 1560 – 150

=1410

Hence Fred got 1410 sweets.

TRY THIS……………………………………… 

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