FUNCTIONS 6

Find remainder when P(x) = x⁵ + 3x³ – x +6  is divided by Q(x)=x+2;

Solution

Let x+2 = 0

x=0-2

x = -2 

Now we substitute x=-2 in P(x).

P(x) = x⁵ + 3x³ – x +6 

P(-2) = (-2)⁵ + (-2)³ – (-2) +6 

P(-2) = -32 + (-8) – (-2) +6 

P(-2) = -32 + (-8) + 2 + 6  

P(-2) = -40 + 8 

P(-2) = -32

So remainder is -32

TRY THIS……………

Find remainder when P(x) = x⁵ - 2x³ – x + 9  is divided by Q(x)=x-3;