PROBABILITY 1

The probability that Azam FC will beat Yanga in the national league is ⁹/16. Find the probability that it won’t be able to do so.

Solution

Let P(E)=  ⁹/16         P(E’) = ?

P(E)   + P(E’) = 1

⁹/16 + P(E’) = 1

P(E’) = 1 -  ⁹/16

P(E’) = ¹⁶/16 -  ⁹/16

P(E’) =  16-9

               16

P (E’) =  7

              11

Hence answer is ⁷/11.

TRY THIS………………………

The probability that Mtibwa FC will beat Mbeya City FC in the national league is ¹³/40. Find the probability that it won’t be able to do so.