POPULATION DECAY 1

A settlement has a population of 2000 people. Each year 12%of the people leave the settlement. How many people will remain after 3 years?

solution

f(t) = A ( 1 -12/100)^t

= 2000(1 – 0.12)^t

= 2000 x (0.88)³

= 2000 x 0.88x 0.88x 0.88

= 2000 x 0.681472

= 1362.944 (1363 approximate)

Therefore there will be 1363 people remaining after three years of decay

TRY THIS………….

A settlement has a population of 5000 people. Each year 5%of the people leave the settlement. How many people will remain after 4 years?