ALGEBRA J2

 

Ana, Joy and Fred shared 1000 sweets such that Ana got 20 sweets less than Joy while Fred got three as much as what Ana got. Find those given to Fred.

 

Solution

 

The starting point is Joy. Let the sweets given to Joy be x. See the table below:

 

ANA	JOY	FRED
x-20	x	3(x-20)=3x-60

  

Then;

 

ANA + JOY + FRED = 1000

 

x-20 + x + 3x-60 = 1000

 

x + x + 3x - 60 - 20 = 1000

 

5x - 80 = 1000

 

5x = 1000 + 80

 

5x = 1080

 

5x = 1080

5       5

 

x = 216

 

The sweets given to Fred

 

= 3x – 60

 

= 3(216) – 60

 

= 648 – 60

 

= 588

 

Hence Fred got 588 sweets.

 

 

TRY THIS………………………

 

 

Ali, James and Kaisiki shared 600 sweets such that Ali got 40 sweets less than James while Kaisiki got three as much as what Ali got. Find the sweets given to Kaisiki.