The 1st term of an
A.P. is 80 and the common difference is 29. Find the 10th term.
Solution
A1= 80, d =
29
An = A1 +
(n-1)d
A10 =
A1 + (10-1)d
A10 =
A1 + 9d
A10 =
80 + (9x29) [ after substituting A1=
80, d = 29 as given above]
∴ A10 =
80 + 261
A10 = 341
Hence the 10th term is
341.
TRY THIS……………
The 1st term of an
A.P. is 55 and the common difference is 160. Find the 12th term.
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