GEOMETRY J3

 Find the midpoint of a line from (3, 12) to (5, 20)

Solution

x1=3, x2=5, y1=12,y2=20.

Mid point = (x1 + x2, y1 + y2)

                         2           2

Mid point = (3 + 5,  12 + 20)

                         2          2

Mid point = (8, 32)

                     2    2

Hence midpoint = (4, 16)

TRY THIS……………………..

Find the midpoint of a line from (-9, 18) to (17, -4)

BINARIES J1

p*q =(p-q)(6p+q) Find (2*-3)

solution

=(p-q)(6p+q)

=[2-(-3)][(6x2)+(-3)]

=[2+3][12+(-3)]

=(5)(9)

=45

Hence (2*-3) = 15

TRY THIS……………….

 

 If p*q =(5p-q)(6p+q) Find (3*-4)