Thursday, 13 March 2025

GEOMETRY J3

 Find the midpoint of a line from (3, 12) to (5, 20)


Solution

x1=3, x2=5, y1=12,y2=20.


Mid point = (x1 + x2y1 + y2)
                         2           2

Mid point = (3 + 5,  12 + 20)
                         2          2

Mid point = (832)
                     2    2

Hence midpoint = (4, 16)

TRY THIS……………………..



Find the midpoint of a line from (-9, 18) to (17, -4)

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