The 1st term of a geometric progression is 7 and the 5th term is 112. Find i)the common ratio. ii) 10th term
Solution
G1=7, G5=112, n=5
i) Gn = G1rn-1;
G5 = G1r5-1;
G5 = G1r4;
112 = 7 x r4;
112 = 7r4;
7 7
16 = r4; Finding the fourth root
of 16,
r = 2
Hence the
common ratio is 2.
ii) 10th term
Gn = G1rn-1;
G10 = G1r10-1;
G10 = G1r9;
G10 = 7 x 29;
G10 = 7 x 512;
G10 = 3584
Hence the eighth term is 3584
TRY
THIS…………………………..
The 1st term of a geometric progression is 2 and
the 6th term is 486. Find i) the common ratio. ii) 11th term.
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