The 1st term of an A.P. is 78 and
the common difference is 45. Find the 10th term.
Solution
A1= 78, d = 45
An = A1 +
(n-1)d
A10 = A1 +
(10-1)d
A10 = A1 + 9d
A10 = 78 + (9x45) [ after substituting A1= 78, d = 45 as given
above]
∴ A10 = 78 + 405
A10 = 483
Hence the 10th term is 483.
TRY THIS……………
The 1st term of an A.P. is 140 and
the common difference is 23. Find the 18th term.
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