Given
that one of the roots of the equation 3x2 + m(x+1) + 5 = 0 is 2,
find m.
Solution
Substitute
x=2, in the above equation.
3(2)2 + m(2+1) + 5 = 0
(3x4) +
(m x 3) + 5 = 0
12 + 3m
+ 5 = 0
3m + 17
= 0
3m = -17
3m = -17
3 3
m=-17/3
Hence m=-17/8
TRY THIS…………………………..
Given
that one of the roots of the equation 4x2 + m(x+1) + 10 = 0 is 8,
find m.
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