SETS 1

If n(AnB)=46, n(B)= 96 and n(AuB)= 140, find n(A)

Solution

n(AuB) = n(A) + n(B) - n(AnB)

140 = n(A)  + 96 - 46

140 = n(A)  +  50

140 - 50 = n(A) 

90 = n(A) 

Hence n(A)  = 90 answer

TRY THIS………….

If n(AnB)=40, n(B)= 98 and n(AuB)= 175, find n(A)