A line passes through (9a, 7) and
(8, 5a). If its slope is 2, find a.
Solution
x1=9a, y1 = 7, x2 = 8, y2 = 5a
Slope(m) = y2 –
y1
x2 – x1
2 = 5a – 7
8 – 29a
2 = 5a – 7 [cross multiplying]
1
8 – 9a
2(8 – 9a) = 5a – 7
16 – 18a = 5a – 7
16 – 18a + 7 = 5a
16 + 7 = 5a+ 18a
23 = 23a
23 = 23a
23 23
1 = a
Hence a = 1
TRY THIS.................................
A line passes through (2a, 5) and (4,
6a). If its slope is 8, find a.