Friday, 1 May 2015

LOGARITHMS 2




If log 2= 0.3010; find the value of log 25,000 without using tables.

solution

log25000=log(100,000÷ 4)

=log100,000 - log4

=log105 – log22

=5log10 – 2log2

=(5x1) – 2(0.3010)

=5– 2(0.3010)

=5 – 0.6020

= 4.398

Hence log25 = 4.398


TRY THIS……………

If log 2= 0.3010; find the value of log 5000 without using tables.


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