Find
n if a line which passes through (-11, -8) and (6,n) has a slope of -1/17
Solution
x1
= -11, y1 =-8, x2 = 6, y2 =
n
m
= y2 –y1
x2
– x1
-1
= y2 –y1
17
x2 – x1
-1 = n –(-8)
17
6 –(-11)
-1
= n + 8
17
6 + 11
-1
= n + 8
17
17
17(n+8)
= -1 x 17
7n
+ 136 = -17
7n
= -17 - 136
7n
= -153
7n = -153
7 7
n
= -9
TRY THIS………………………
Find
t if a line which passes through (6, -2) and (-3,t) has a slope of 1/9
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