A bag
contains 12 red balls and 8 blue balls. Two balls are taken from the bag. What
is the probability that they are both blue?
Solution
(This is a
problem with replacement)
n(R) = 12,
n(B) = 8, n(S) =20
P(B) = n(B)
n(S)
1st pick =
8/20
2nd pick =
8/20 as well.
P(B) = 8 x
8
20 20
P(B) = 64
= 4
400 25
Therefore
Probability of drawing a blue ball is 4/25
TRY THIS ..............
A bag
contains 10 purple stones and 12 blue stones. Two stones are taken from the
bag. What is the probability that they are both blue?
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