A bag contains 4 red balls
and 6 blue balls. Two balls are taken from the bag. What is the probability
that they are both red?
Solution
(This is a problem with
replacement)
n(R) = 4, n(B) = 6, n(S) = 10
P(R) = n(R)
n(S)
P(R) = 4
10
1st pick = 4/10
2nd pick = 4/10 as
well.
P(RR) = 4
x 4
10 10
P(RR) = 16 /100
= 4/25
Therefore Probability
of drawing a red ball is 4/25
TRY THIS
..............
A bag contains 9 purple
stones and 11 blue stones. Two stones are taken from the bag. What is the
probability that they are both purple?
No comments:
Post a Comment